Bloomfield Township, LaGrange County, Indiana

Township in Indiana, United States

41°38′56″N 85°21′31″W / 41.64889°N 85.35861°W / 41.64889; -85.35861CountryUnited StatesStateIndianaCountyLaGrangeGovernment

• TypeIndiana townshipArea

• Total35.85 sq mi (92.9 km²) • Land35.58 sq mi (92.2 km²) • Water0.27 sq mi (0.7 km²)Elevation

^[1]

945 ft (288 m)Population

(2020)^[2]

• Total5,746 • Density152.1/sq mi (58.7/km²)FIPS code18-05752^[3]GNIS feature ID453113

Bloomfield Township is one of eleven townships in LaGrange County, Indiana. As of the 2020 census, its population was 5,746 (up from 5,412 at the 2010 census^[4]), and it contained 2,270 housing units.

Bloomfield Township was founded in 1835.^[5]

Geography

According to the 2010 census, the township has a total area of 35.85 square miles (92.9 km²), of which 35.58 square miles (92.2 km²) (or 99.25%) is land and 0.27 square miles (0.70 km²) (or 0.75%) is water.^[4]

References

^ "US Board on Geographic Names". United States Geological Survey. October 25, 2007. Retrieved January 31, 2008.
^ "Census Bureau profile: Bloomfield Township, LaGrange County, Indiana". United States Census Bureau. May 2023. Retrieved April 2, 2024.
^ "U.S. Census website". United States Census Bureau. Retrieved January 31, 2008.
^ ^a ^b "Population, Housing Units, Area, and Density: 2010 - County -- County Subdivision and Place -- 2010 Census Summary File 1". United States Census. Archived from the original on February 12, 2020. Retrieved May 10, 2013.
^ Counties of LaGrange and Noble, Indiana: Historical and Biographical. F.A. Battey & Company. 1882. p. 126.